Feb 15, 2026 · 4 I try calculate this integral. Probably, I can change the of integrals and first try the integral over $\theta$, but the problem is that an improper integral follows...

The integral which you describe has no closed form which is to say that it cannot be expressed in elementary functions. For example, you can express $\int x^2 \mathrm {d}x$ in elementary functions …

@user599310, I am going to attempt some pseudo math to show it: $$ I^2 = \int e^-x^2 dx \times \int e^-x^2 dx = Area \times Area = Area^2$$ We can replace one x, with a dummy variable, move the …

Feb 4, 2018 · The integral of 0 is C, because the derivative of C is zero. Also, it makes sense logically if you recall the fact that the derivative of the function is the function's slope, because any function f …

Oct 11, 2025 · However, one "intrinsic integral closure" that is often used is the normalization, which in the case on an integral domain is the integral closure in its field of fractions. It's the maximal integral …

Feb 6, 2026 · Evaluate an integral involving a series and product in the denominator Ask Question Asked 1 month ago Modified 30 days ago

If by integral you mean the cumulative distribution function $\Phi (x)$ mentioned in the comments by the OP, then your assertion is incorrect.

Dec 15, 2017 · A different type of integral, if you want to call it an integral, is a "path integral". These are actually defined by a "normal" integral (such as a Riemann integral), but path integrals do not seek to …

May 28, 2021 · I am having difficulties to compute this integral $$ \int_ {-\infty}^\infty e^ {\pm ix^2} \, dx. $$ I tried to use complex integration and Cauchy's theorem but it didn't work. Can someone help me?

How to show that: $$\int_ {0}^ {1}\frac {\tan^ {-1}\sqrt {x^ {2}+2}} { (x^ {2}+1)\sqrt {x^ {2}+2}}\mathop {\mathrm {d}x}=\frac {5\pi ^ {2}} {96}$$ I saw this on Wolfram.